Attenuator pads
Attenuator pads with explicit circuit assumptions and worked equations.
Development preview. Check the assumptions below before relying on a result. Calculations run in your browser.
How it calculates
Matched amplitude ratio: k = 10^(attenuation/20)
Power balance: Pload = Pin 10^(−loss/10)
Assumptions
- Pin is power entering the terminated pad, excluding the source termination. All impedances are purely resistive. T has two equal series arms; pi has two equal shunt arms; bridged T has two Z0 series arms and a resistor bridging input to output. L orientation: series first when source impedance is higher; shunt first when source is lower.
Worked example
These are the calculator's default inputs. Change any input above to recalculate.
Inputs
- Topology
- t
- Attenuation
- 6 dB
- Source impedance
- 50 Ω
- Load impedance
- 50 Ω
- Power entering pad
- 0.1 W
Results
- Series resistor
- 16.6139 Ω
- Shunt resistor
- 66.931 Ω
- Voltage attenuation ratio
- 0.501187
- Insertion loss
- 6 dB
- Bridge resistor
- Not used Ω
- Load power
- 0.0251189 W